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No because I already can guarantee someone will mess up and not follow the rules even if there is a way

what if i dont have a dollar

Everyone just needs to bring a dollar with their number on it and swap it out…..

0.5/100 = 0.005% = a 1 in 200 chance of winning a 101 fold increase on your money so you should not take the bet because in the long run, it isnt feasible you would play 200 times spending £200 and winning £101

The odds of winning are 2 to the 50th

Shouldn’t lose be -$1 since you lost a dollar by betting?

Theres always that one troll who is willing to not win $101 just to ruin everyone elses money.

Dont take it. its a scam.

Take the bet and the strategies is look in your # box and go to the box your bill u found says

I’ll only lose a dollar so I’ll go for it, fun story to tell others.

1/2^n … when (n) = 100 then you get 1/2^100 …. however for just $1 ? I think you should totally take the bet lol

Should I bet $1 for the almost impossible chance of winning 1 cent? Yeah, I think Ill pass up on that wonderful opportunity…..

you first chose any random box then if it has yoir bill GOOD LUCK but if no and you went to box 7 and the bill says 90 go to the 90 box and keep on going

No don’t take the bet, the more people or subjects you have in the bet the less change you have.

This is just like the riddle on Ted Ed

Well ill just try, 1 dollar wont hurt i guess

Would you have to multiply the probabilities (0.31^100) ?

Bet battle royale

Yes of course u should but i am lazy

go to 50 box..

take the bill out…

and leave with 50$..

thats 50$ payout..

or bribe minutephysics 50$ and leave with 50$..

simple

Who cares about the money at this point? This is a huge waste of time.

Yes potential 100$ pay, the odds are low, but its only a buck

TED ED

Go to Box 1. The number on the dollar bill in it denotes your next destination. For example, the dollar bill numbered 34 is on box 1. Go to box 34. Inside it, you find a dollar bill with 36 on it. Go to box 36. Repeat the process over and over again.

who wouldn’t take the bet? if you lose, then you lose $1 not a big deal. but if you win you get $100 more than you started with.

No its impossible to win. For each person finding his dollar bill has a probability of 1/2. The probability will remain same as we are only allowed to at half the boxes. So for everyone to find their Bill the probability is {100C100 x (1/2)^0 x(1/2)^100} x 100.. which is ..0.0000(25 more 0)076 %. or 7.88×10^-29%. Anyone would be an Idiot who would take the bet as the probability of success of almost impossible. Failure probability is 99.9999…………(26 more 9)%. Its like tossing a coin 100 time, and we only win if we get tails or head all of the 100 times which is odd :?.

Sure I would take the best because if I lose I only lose 1 dollar. Is not like a casino were you lose all your life savings on gambling.

Basically… you need to maintain a closed loop. i.e rather than random searching of the boxes the system should be that you start with your number. So if I’m 17, I look in box 17 and if I find bill number 66, I then look in box 66 etc. So the chance that the loops will be 50 or less is about 30% and tbh you’re only losing a dollar so yes.

I’d take it. Go to the box with your og number in it. After, go to the box with the number that has the number of the bill you just grapped on it. No idea how this works, saw it on a Ted Riddle video once.

Odds are 0.5^100. That’s appalling definitely not worth it.

B-but I’m Canadian…we don’t have one dollar bills…sorry.

the probability to get one in the first box is 1/100, and then the 2nd box is 1/99, and so on. the last addition is + 1/51 for the 50th box you open. the addition of all these gives 0,69314… So thats like 69% for each person to find their bill. for 100 people, we have to put that fraction exponent 100, and that gives 0, 000 000 000 000 000 120 9… probability. thats a super small fraction so the answer is no, you dont take the bet.

Solution: dont gamble

this bet is what a bullshit

TIP1:dont get confused by a big numbers

Yes I would take the bet and I would arrange the other people to do the same as me: number one goes in and looks in the first box, lets say he finds number 50, he will then go to the 50th box and look inside … Repeat this pattern for every player and everyone will find their number.

Its the same as the Ted-Ed riddle! Probability approaches 30%!!

Take the bet and follow the chain

I know the solution, but there will always be that one guy who screws it up for everyone.

Solution: Open the box with your number than whatever number bill it is go to that number box and so on until you find your bill

This has a 35% chance of working and getting $101 (unless they completely ignore you)

I would take the bet

Yeah, Im feeling lucky.

impossible since the probability of finding the bill in 50 boxes, ie 50/100 narrows down to 1/2 probability of finding the bill

once its a 100 people, theres no way atleast one wont fail

Ted Ed did a video about this, its really easy

Chose the number on your bill. Then chose the number that was in the box. For example if you had bill #1 chose box one, and in box one there’s bill number 3 chose 3

Just bring a sharpie and number the boxes

I would take it

.

Plot twist: We all lose because drawn-on bills aren’t legally acceptable.

I would because your only risking a dollar

Dont take it because even if you win since you must put in your own dollar if you win you just get your own doolar back

i bet he’s only making this bet because he wants to pay back his friends for all the boxes he bought on accident

After you find your money you can go play music.

Thank you for putting this in my recommended

The people line up outside the room from with their numbers 1 to 100 in order. The first guy will search all of the boxes on the left side of the room. (Note that this has a 50% chance of sucess because it is over if the first guy does not find his own bill) (The following is a stretch, because you are communicating with the people in the line, even though you are not going back to the group in the beginning. Im a rebel) The first person will then yell out left, or right, (depending on which side they chose) and then yell every number on that side. Hopefully the first person also finds his own on that side, which is bill number 1. If number 2 heard 2 yelled by the first person, they will go to the same side the first person went, (note that the first person also calls out which side they went, left or right) and go through all of those boxes until they find their own. If the second person does not hear 2 yelled by the first person, they will instead go the opposite direction. People 3-100 will do the same thing that person 2 did. Note that 2-100 will need to remember if person 1 called their number or not, but if $101 is on the line they should remember.

Its just 1/2 times by 1/2 100 times. The chances youll win is like 1 out of 999999999999 or something like that

No

Answer (l am actually serious)

Yes take the bet.

For example: You had the 64th bill

1. Go to the 64th box

2. (Assume its the 21st bill in the box) Go to the 21st box

3. Repeat the same process, you will get your bill.

Merry Happy you copied me so delete your little cheating comment.

@UCZFUstqOkja2GqIttvB5nnA

They show the answer its a bit different but

No, it has impossible right in the title.

Steal all the boxes

Alternative challenge: find your dollar bill as fast as possible

U open first box and for example if on the bill there is number 32 u go to 32nd box and u find bill with number 71 and u go open that box and so on there is more than 68% that u are going to make it

Maybe…😏. Happy 6th aniversary

CorgiMan you got that from ted ed

1) pick the that is of the same number as your bill (eg you number is 48 you go to the 48th box)

2) if it is your bill, congrats. If it is not go to the box that is of the same number as the note you saw (eg. You see 56 you go to the 56th box)

3) every player does this, the chances of success are around 35%

Solution I think

The first person goes in the room and check the box that has his number (for example his number is 38 he will go to box 38 and check in the box).if the number is 47 he will go to box nuber 47 and check in that box.he will do repeat this until he finds his number.

The next person who goes in will do the exact same but start with his/her number.

Tell me if Im right or am I to late

Take the bet!! When you open a box proceed the the box with the corresponding bill number and continue this pattern until you find your bill

Tell them to go to the box that has the same number as the one on the bill

I would take the bet and what I would do is look in one box then go to a number box with the bill until I did the 50 turns or found my bill

At the end if all 99* of you…

“Do you take the bet?”

*looks at title*

Yea like I even have a dollar lol

Stupid bet is stupid

Open the box of ur number (so person 16 will open box 16 in the line) and if thats ur bill ur done! If not open the box of that bill on it (so if box 16 has bill 28 in it u open box 28) keep on going till u find ur bill cause this has a fairly high chance of success. And yes because if u loose u loose $1 or €1 or £1 whatever it currency is but of u win u get 100 of whatever ur currency is.

100%

I’d just take it even if I lose it’s only one dollar

Thats easy since you dont check who is on what order, everyone agrees to open one box and fake that it was his real line number, the first opens the first box, the next the second box etc..

First you choose your bill number box then the next one you get on the bill and then reapeat and so on odds are 35% i think i already knew i learned u can aldo see it in Vsauce

but why is it a problem tho like who does it hurt

the odds of no person fails is this- 1/2^100 right ?

Yes

IT IS SOLVEABLE.

Say you had the 45 box, go to there and see what number is there. If it’s 74 go to the 74th box. Repeat = PROFIT.

That’s a very poor bet, never take it. The chance of winning is extremely small. People say it is 50% but they don’t realize that there are 100 people, the only way to win is for all of them to pass so thus the chance of winning would be 100*0,5^100 ≈ 7,8^-29 %

Goodluck xD

when they write the number on the 1 dollar bill they can write 2 numbers on either side so on one side there would be the number 1 and the other side number 2. so if they can only view 50 boxes it would be sure that they would find their number.

You shouldnt take the bet cause theres no way 100 random people will successfully execute any strategy or even come up with one haha.

What if everybody takes whatever bill they see first and not necessarily their own? Insta win, since who would record everybodys number on their dollar.

0:07 Someone with a degree in Physics teaching people on the Internet how to add 1.

30 %

50% chance per person. 100 people. 1 outcome of success = 0,5^100. Take the bet? nahhhhh

The strategy is simple tell all the participants to lie that they got the same number what they supposed to get simple

lottery tickets simplified….. one winning answer, everyone pools their money into the gamble, the rules are made to screw you all and the odds of winning is microscopic.

never take this bet.

Jokes on you I have teleconises

Assuming the boxes are labeled, first go to your number box and then go to the box which corresponds to the one you found in yours. Do that for each bill you find until you find yours.

I bet you ten dollars that you wont give me ten dollars.

1: Enter the room

2: Take a dollar out of 50 boxes

3: Run as fast as you can

Take the bet:

1. First person to go in chooses his number(Example:6) box.

2. So he goes to box number 6. If the number inside is 64, he shall proceed to box 64.

3. Repeat the process until the box is found.

Me too

Aaron Foo I watch this on ted ed too

Ted ed had the same concept

Dude you found it in his other video

Id take the bet 1$ isnt much to lose but 100$ is pretty good to win.

So, pessimistically, 0.5^100?

Still, one dollar buy in and 101 dollar pay out is always a bet worth taking.

Solution: go get a random box. Look the bill number nad go to the box corresponding that number. Repeat as long as it takes to find your bill.

Yes, because if I lose, I only lose $1

I would take the bet. Go into the room. Open ALL the boxes and take out EVERYONES Dollars, walk out, tell the guy you couldnt find your dollar and walk away with the jackpot in your pockets.

I did reaserch and it was 20% chance. (Just saying)

You should take the bet an use this strategy:

Every person that enters the room choose the box that matchs with the number that you wrote on your dolar at the beginig. If your dolar is not there you look at the number on the dolar and continue to look on the box that matchs with the number of the last dolar you just saw. If you conitinue and follow this process and every single person follows this strategy you all have maybe a 30 percent chance of winning. It is a very good deal knowing you have a 10100% profit for a 30% chance of wining

So here’s a thing that does somewhere around 30 percent of winning

So look in the first box, the number of the dollar bill in there will be your next box and so on

You copied me weirdo.